3y^2+0y-48=0

Solution for 3y^2+0y-48=0 equation:

Simplifying
3y2 + 0y + -48 = 0

Anything times zero is zero.
3y2 + 0y + -48 = 0

Reorder the terms:
0 + -48 + 3y2 = 0

Combine like terms: 0 + -48 = -48
-48 + 3y2 = 0

Solving
-48 + 3y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '48' to each side of the equation.
-48 + 48 + 3y2 = 0 + 48

Combine like terms: -48 + 48 = 0
0 + 3y2 = 0 + 48
3y2 = 0 + 48

Combine like terms: 0 + 48 = 48
3y2 = 48

Divide each side by '3'.
y2 = 16

Simplifying
y2 = 16

Take the square root of each side:
y = {-4, 4}